1.
CREATE DEPARTMENT TABLE
create table department(
department_id number,
department_name varchar(30),
department_block_number number,
constraint pk primary key(department_id)
);
2.CREATE STUDENT TABLE
create table student(
student_id number,
student_name varchar(30),
address varchar(40),
city varchar(30),
department_id number,
constraint pk primary key(student_id),
constraint fk foreign key(department_id) references Department(department_id)
);
3.CREATE MARK TABLE
create table mark(
value number,
subject_id number,
student_id number,
constraint pk primary key(subject_id,student_id),
constraint fk foreign key(subject_id) references Subject(subject_id),
foreign key(student_id) references student(student_id)
);
4.CREATE SUBJECT TABLE
create table subject(
subject_id number,
subject_name varchar(30),
subject_code varchar(10),
staff_id number,
constraint pk primary key(subject_id),
foreign key(staff_id) references staff(staff_id)
);
5.ADD A COLUMN IN STUDENT TABLE
alter table student add age number(2);
6.ADD A CONSRAINT TO COURSE TABLE
alter table course
add constraint chk_fees check(fees>0);
7.ADD A COLUMN IN REGISTRATION TABLE
alter table registration
add DOC DATE;
alter table registration
add constraint check_date check(doc>doj)
8.DROP REGISTRATION TABLE
drop table registration;
9.DROP STUDENT TABLE
drop table registration;
drop table student;
10.TEST YOUR UNDERSTANDING 1
create TABLE product
( prod_id number(4),
prod_name varchar2(25),
prod_expiry_date date not null,
primary key(prod_id)
);
11.TEST YOUR UNDERSTANDING 2
CREATE table department
( dept_id number(4),
prod_id number(4),
dept_name varchar(25) unique,
dept_head varchar2(25) NOT NULL,
PRIMARY KEY(dept_id),
foreign key(prod_id) REFERENCES product(prod_id)
);
#DATA MANIPULATION LANGUAGE
1.INSERT RECORDS-DEPARTMENT
insert into department values(1, 'CSE', 3);
insert into department values(2,'IT', 3);
insert into department values(3,'SE',3);
2.INSERT RECORDS-STUDENT
insert into student values(1,'Anandhi','LMC','Coimbatore',1);
insert into student values(2,'Anitha','ABC','Salem',2);
3.INSERT RECORDS-STAFF
insert into staff values(3,'Senthil',2);
insert into staff values(4,'Santhya',2);
insert into staff values(5,'Geetha',3);
4.INSERT RECORDS SUBJECT
insert into subject values(1,'English','E1',2);
insert into subject values(2,'Maths','M1',4);
insert into subject values(3,'Physics','P1',1);
5.INSERT RECORDS-MARKS
insert into mark values(98,1,1);
insert into mark values(88,2,1);
insert into mark values(78,3,1);
6.INSERT RECORDS INTO COURSE TABLE
insert into course values(1001,'Java',4,5000);
insert into course values(1002,'C++',2,4000);
insert into course values(1003,'Linux and C',3,4000);
insert into course values(1004,'Oracle',2,3000);
insert into course values(1005,'CSharpe',6,10000);
7.UPDATE FEES FOR SHORT COURSES
update course set fees=fees+(-500)
where duration<=3;
8.QUPDATE ADDRESS OF A STUDENT
update student set student.street='Andheri West', student.city='Mumbai'
where student.firstname='Abdul' And student.lastname='Rahman';
9.REMOVE REGISTRATION DETAILS
delete from registration where
DOJ='25-May-18';
10.REMOVE COURSE DETAILS
delete from registration;
delete from course where
duration <= 3;
#SELECT STATEMENT
1.LIST DEPARTMENT NAMES
select department_name from department order by department_name;
2.LIST OF STUDENT NAMES
select student_name from student where student_id!=4 and student_id!=7 order by student_name;
3.DEPARTMENT NAME BASED ON BLOCK NUMBER
select department_name from department where department_block_number=3 order by
department_name;
4.DISPLAY STUDENT DETAILS
select student_name from student order by student_name;
5.STUDENTS NAME STARTS WITH A
select student_name from student where student_name like 'A%' order by student_name;
6.STUDENT NAME BASED ON START AND ENDING CHARACTER
select student_name from student where student_name like 'A%a' order by student_name;
7.STUDENT DETAILS BASED ON CITY
select studid,firstname from student where
city='Coimbatore' and dob='08-Oct-97' or
city='Chennai' and dob='08-Oct-97'
order by studid;
8.DISPLAY STUDENT LOCATION
select distinct city from student order by city;
9.STUDENT NAME BASED ON CONDITION
select firstname from student where firstname like 'S%n' order by firstname;
10.STUDENT DETAILS BASED ON LOCATION AND DATE OF BIRTH
select studid,firstname from student where
city='Coimbatore' and dob='08-Oct-97' or
city='Chennai' and dob='08-Oct-97'
order by studid;
11.STUDENT ID BASED ON COURSE
select distinct studid from registration where courseid in (1001,1005) order by studid;
#FUNCTION-SCALAR&AGGREGATE
1.LIST DEPARTMENT NAME
select lower(department_name) as dept_name from department
order by dept_name;
2.STUDENT ADDRESS
3.CONCATINATING DETAILS
select (address || ', ' || city) as Address from student
order by Address desc;
4.LENGTH OF STUDENT NAME
select student_name from student where length(student_name)=6
order by student_name;
5.NUMBER OF DEPARTMENTS
select department_block_number,count(department_id) as NO_OF_DEPT from department
group by department_block_number
order by NO_OF_DEPT desc;
6.STUDENT COUNT
select count(student_name) as STUD_COUNT from student;
7.AVERAGE MARK
1.select max(round(avg(value),2)) as avg_mark from mark
group by student_id;
2. select max(round(avg(value),2)) as avg_mark from mark
group by student_id;
8.MINIMUM MARK
select student_id,min(value) as minimum_mark from mark
group by student_id
order by minimum_mark;
9,NUMBER OF BUSES
select type as bus_type,
count(avail_seats) as bus_count
from buses
group by type
order by bus_count desc;
10.AVERAGE MARK GREATER THAN 80
1.select student_id , round(avg(value),2) as avg_mark
from mark
group by student_id
having avg(value) > 80
order by avg_mark;
2. select student_id , round(avg(value),2) as avg_mark
from mark
group by student_id
having avg(value) > 80
order by avg_mark;
11.STUDENT NAME
select (firstname || ' ' || lastname) as STUDENTNAME
from student
order by STUDENTNAME;
12.STUDENT ID BASED ON JOINING MONTH
13.DISPLAY STUDENT NAME ALONG WITH AGE
select studid,firstname,trunc(months_between(sysdate,dob)/12) as age from student
order by studid;
14.LATEST DATE OF REGISTRATION
select max(doj) as LATESTDATE from registration;
15.NUMBER OF COURSES REGISTERD
#JOINS&SUBQUERY
1.SUBJECT WITH STAFF DETAILS
select subject_name,subject_code,staff_name from subject s
inner join staff f
on s.staff_id=f.staff_id
order by subject_code;
2.STUDENT AND THEIR DEPARTMENT BASED ON CITY
select student_name,department_name from department
inner join student
on student.department_id=department.department_id
where lower(city)='coimbatore'
order by student_name;
3.STUDENT NAME BASED ON DEPARTMENT
select student_name from student
where department_id in(select department_id from department where lower(department_name)='it')
order by student_name desc;
4.DEPARTMENT WITH STUDENT COUNT
select department_name,count(student_name) as student_count
from department inner join student on student.department_id=department.department_id
group by department_name
order by department_name ;
5.DEPARTMENT WITH STAFF COUNT
select d.department_name,count(s.staff_id) as staff_count
from department d ,staff s
where d.department_id=s.department_id(+)
group by department_name
order by department_name;
6.DEPARTMENT HAS MAXIMUM STAFF
select department_name from department where department_id in
(select department_id from staff
having count(department_id) in
(select max(count(department_id)) from staff
group by department_id)
group by department_id)
order by department_name;
7.DEPARTMENT HAS LEAST STUDENT COUNT
select department_name from department where department_id in
(select department_id from student having count(department_id) in
(select min(count(department_id)) from student
group by department_id)
group by department_id)
order by department_name;
8.STUDENT WITH MINIMUM MARK
select subject_name,min(value) as min_mark from subject
join mark using(subject_id)
where value in(select min(value) from subject )
group by subject_name
order by subject_name desc;
9.STUDENT MARK IN PARTICULAR SUBJECT
select student_name,value from mark
join student using(student_id)
join subject using(subject_id)
where lower(subject_name)='theory of computation'
order by student_name;
10.STUDENT NAME WITH THEIR HIGHEST MARK
select student_name,max(value) as max_mark from student
join mark using(student_id)
group by student_name
order by student_name;
11.MAXIMUM MARK IN SUBJECT WITH STAFF NAME
select staff_name,subject_name,max(value) as max_mark from subject
join staff using(staff_id)
join mark using(subject_id)
group by staff_name,subject_name
order by max_mark desc;
12.BLOCK NUMBER BASED ON MAXIMUM DEPARTMENT LOCATED
select department_block_number from department
where department_block_number in(select max(department_block_number) from department
group by department_block_number;
13.STUDENT NAME LIST BASED ON DEPARTMENT NAME
select student_name from student where department_id in
(select department_id from department where lower(department_name)='cse')
group by student_name
order by student_name desc;
14.DEPARTMENT NAME WITH MAXIMUM STUDENT COUNT
select department_name from department natural join student
group by department_name
having count(student_id)=(
select max(stu_count) from
select department_name, count(student_id) as stu_count
from department natural join student
group by department_name
);
15.STAFF BASED ON DEPARTMENT
select staff_name from staff where department_id in
(select department_id from department where lower(department_name)='it')
order by staff_name;
16.STAFF DETAILS BASED ON SUBJECTS
select staff_name from staff where staff_id in
(select staff_id from subject)
order by staff_name;
17.STAFF DETAILS WITHOUT HANDLING ANY SUBJECTS
select staff_name from staff where staff_id not in
(select staff_id from subject)
order by staff_name;
18.STUDENT DETAILS BASED MARK SCORED
select student_name from student
join mark using(student_id)
group by student_name
having min(value)>50
order by student_name;
19.MAXIMUM SCORE IN THE PARTICULAR SUBJECT
select student_name from student
join mark using(student_id)
join subject using(subject_id)
where subject_name ='Software Engineering'
and value=(select max(value)
from mark join subject using (subject_id)
where subject_name ='Software Engineering')
order by student_name;
20.STUDENT DETAILS WITH SUBJECT NAME
select subject_name,student_name
from student s
inner join mark m on s.student_id=m.student_id
inner join subject su on m.subject_id=su.subject_id
inner join (select subject_id,
max(value) as maximum
from mark ma group by subject_id)
highmarks on highmarks.subject_id=m.subject_id
and highmarks.maximum=m.value
order by subject_name, student_name;
21.STUDENT NAME WITH COMPUTER PROGRAMMING MARKS
select student_name,value as CP_MARKS from mark
join student using(student_id)
join subject using(subject_id)
where lower(subject_name)='computer programming'
order by value , student_name desc;
22.TOP PERFORMER IN SOFTWARE ENGINNERING
select student_name,department_name,max(value) as value
from mark
inner join student on student.student_id=mark.student_id
inner join subject on subject.subject_id=mark.subject_id
inner join department on department.department_id=student.department_id
where value in(select max(value) from mark
inner join subject on subject.subject_id=mark.subject_id
where
lower(subject_name)='software engineering') and
lower(subject_name)='software engineering'
group by student_name,department_name
order by department_name ;
23.SECOND MAXIMUM FEES
24.STUDENT NAME AND COURSE NAME
25.STUDENT NAME ALONE WITH DOJ AND DOC
26.SUDENT ID WITH TOTAL FEES
27.TOTAL FEE COLLECTED FEOM EACH COURSE
28.COUSE NAME BASED ON NUMBER OF STUDENTS REGISTERED
#DATA CONTROL LANGUAGE&DATABASE OBJECTS
1.CREATE VIEW_MOBILE
1.STUDENT ADDRESS
select student_id,address
from student
where initcap(student_name)='David';
2.STUDENT NAME AND COURSE NAME
select firstname,coursename
from student s
inner join registration r on s.studid=r.studid
inner join course c on r.courseid=c.courseid
order by firstname asc,coursename asc;
3.TOTAL FEE COLLECTED FOM EACH COURSE
select c.courseid,c.coursename,(count(r.studid)*c.fees)as TOTALFEES
from course c inner join registration r
on c.courseid=r.courseid
group by c.courseid,
c.coursename,
c.fees
order by c.courseid;
4.SECOND MAXIMUM FEES
select courseid,coursename
from course
where fees=(select max(fees) from course where fees<(select max(fees) from course)
order by courseid;
5.COURSE NAME BASED ON STUDENT REG
select c.coursename
from course c
inner join registration r
on r.courseid=c.courseid
group by c.coursename
having count(c.courseid)>=2
order by coursename;
6.STUDENT ID BASED ON JOINING MONTH
select distinct studid
from registration
where to_char(doj,'MM')=6
order by studid;
7.STUDENT NAME ALONG WITH DOJ AND DOC
select s.firstname,
r.doj,
add_months(r.doj,c.duration)as doc
from registration r
inner join student s on s.studid=r.studid
inner join course c on c.courseid=r.courseid
order by firstname,doj,doc;
8.STUDENT DETAILS BASED ON CITY
select student_id,student_name
from student
where (city='Coimbatore')
order by student_name asc;
9.NUMBER OF COURSES REGISTERED
select s1.studid,count(c1.courseid) as NOOFCOURSES
from student s1
join registration r1
on r1.studid = s1.studid
join course c1
on r1.courseid = c1.courseid
group by s1.studid
order by
count(c1.courseid) desc,
s1.studid asc;
10.CREATE VIEW MOBILE
create view customer_mobile_details
as
select c.customer_id,c.customer_name,c.mobile,s.salesid,s.net_amount,
m.model_name,m.manufacturer
from sales_info s
inner join customer_info c
on s.customer_id=c.customer_id
inner join mobile_master m
on s.ime_no=m.ime_no
order by customer_id,customer_name,salesid;
