How to configure a "generic" sharedExample? #692
Description
I want to implement a ValueObjectSharedExampleConfiguration: QuickConfiguration.
class ValueObjectSharedExampleConf: QuickConfiguration {
override class func configure(_ configuration: Configuration) {
sharedExamples("Value Object") {
(context: @escaping SharedExampleContext) in
describe("same objects") {
it("should be equal") {
let obj1a = context()["1a"]
let obj1b = context()["1b"]
expect(obj1a == obj1b).to(beTrue())
}
}
describe("different objects") {
it("should not be equal") {
let obj1 = context()["1a"]
let obj2 = context()["2"]
expect(obj1 == obj2).to(beFalse())
}
}
}
}
}And then I want to test any classes/structs that conforms to Equatable with this shared Example like this:
itBehavesLike("Value Object") { [ "obj1a": foo1a, "obj1b": foo1b, "obj2": foo2] }But the problem is, SharedExampleContext is actually a closure returns [String: Any], so obj1a, obj1b, obj2 variables I get in sharedExample closure are all of type Any, which doesn't necessarily conform to Equatable. Thus the code obj1a == obj1b won't compile.
Actually if I check obj1a is Equatable it returns true. But I don't know how to cast it to a proper type that compiler will accept. obj1a as! Equatable won't compile because Equatable is a generic protocol.
I can't just write obj1a as! Foo because if there is another class Bar: Equatable I want my sharedExample also works for that.
I tried to make the Configuration class generic, it compiled but crashed on itBehavesLike because that configuration class is not configured actually.