Create C语言实现井字棋游戏

Soda-python · web-flow · commit fe2a404b49d2 · 2024-01-12T13:21:15.000+08:00
diff --git a/C语言实现井字棋游戏 b/C语言实现井字棋游戏
@@ -0,0 +1,72 @@
+/*每输入一个1或0后回车，1代表X，0代表O，注意：填充顺序是一行填完三个后，继续下一行如：
+1
+0
+1
+0
+1
+0
+0
+1
+0
+表示:101
+    010
+    010 */
+//代码如下：
+#include <stdio.h>
+int main(){
+	const int size = 3;
+	int board[size][size];
+	int i,j;
+	int numOfX,numOfO;
+	int numOfXX,numOfOO;
+	int result = -1; // -1:没人赢，1：X赢，0：O赢。 
+	//读入矩阵
+	for (i = 0;i<size;i++){
+		for(j=0;j<size;j++){
+			scanf("%d",&board[i][j]);
+		}
+	} 
+	for(i=0;i<size && result == -1;i++){
+		numOfO = numOfX = numOfOO = numOfXX = 0;
+		for (j=0;j<size;j++){
+			if (board[i][j]==1){
+				numOfX ++;
+			} else if(board [i][j] == 0) {
+				numOfO ++;
+			}
+			if (board[j][i]==1){
+				numOfXX++;
+			} else if (board[j][i]==0){
+				numOfOO++;
+			}
+		}
+		if (numOfO == size || numOfOO == size){
+			result = 0;
+		} else if(numOfX == size || numOfXX == size){
+			result = 1;
+		}
+	}
+	if (result == -1){
+		numOfX = numOfO = numOfOO = numOfXX = 0;
+		for(i=0;i<size;i++){
+				if (board[i][i] == 1){
+					numOfX ++;
+				} else if(board[i][i]==0){
+					numOfO ++;
+				}
+				if (board[i][size-i-1] == 1){
+					numOfXX ++;
+				} else if (board[i][size-i-1] == 0){
+					numOfOO ++;
+				}
+				
+		}
+		if (numOfO == size || numOfOO == size){
+				result = 0;
+			} else if(numOfX == size || numOfXX == size){
+				result = 1;
+			}
+	}
+	printf("%d",result);
+	return 0;
+}
