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45 lines (38 loc) · 1.74 KB
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#!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Build word tree of a sentence using NLP (Spacy) approach
@author: saul
"""
#Tree
from __future__ import unicode_literals, print_function
import plac # Plac is a wrapper over argparse and works in all versions of Python starting from Python 2.3 up to Python 3.1
import spacy
@plac.annotations(model=("Model to load", "positional", None, str))
def main(model="en_core_web_sm"):
nlp = spacy.load(model)
print("Loaded model '%s'" % model)
doc = nlp(
"displaCy uses CSS and JavaScript to show you how computers "
"understand language"
)
# The easiest way is to find the head of the subtree you want, and then use
# the `.subtree`, `.children`, `.lefts` and `.rights` iterators. `.subtree`
# is the one that does what you're asking for most directly:
for word in doc:
if word.dep_ in ("xcomp", "ccomp"):
print("".join(w.text_with_ws for w in word.subtree))
# It'd probably be better for `word.subtree` to return a `Span` object
# instead of a generator over the tokens. If you want the `Span` you can
# get it via the `.right_edge` and `.left_edge` properties. The `Span`
# object is nice because you can easily get a vector, merge it, etc.
for word in doc:
if word.dep_ in ("xcomp", "ccomp"):
subtree_span = doc[word.left_edge.i : word.right_edge.i + 1]
print(subtree_span.text, "|", subtree_span.root.text)
# You might also want to select a head, and then select a start and end
# position by walking along its children. You could then take the
# `.left_edge` and `.right_edge` of those tokens, and use it to calculate
# a span.
if __name__ == "__main__":
plac.call(main)