BUGFIX: Bbox union and transform, better semantics

brunobeltran · brunobeltran · commit 92146570dfbe · 2020-04-13T05:23:42.000-07:00
diff --git a/lib/matplotlib/transforms.py b/lib/matplotlib/transforms.py
@@ -660,10 +660,10 @@ def union(bboxes):
         # needed for 1.14.4 < numpy_version < 1.16
         # can remove once we are at numpy >= 1.16
         with np.errstate(invalid='ignore'):
-            x0 = np.min([bbox.xmin for bbox in bboxes])
-            x1 = np.max([bbox.xmax for bbox in bboxes])
-            y0 = np.min([bbox.ymin for bbox in bboxes])
-            y1 = np.max([bbox.ymax for bbox in bboxes])
+            x0 = np.min([bbox.x0 for bbox in bboxes])
+            x1 = np.max([bbox.x1 for bbox in bboxes])
+            y0 = np.min([bbox.y0 for bbox in bboxes])
+            y1 = np.max([bbox.y1 for bbox in bboxes])
         return Bbox([[x0, y0], [x1, y1]])
 
     @staticmethod
@@ -672,10 +672,10 @@ def intersection(bbox1, bbox2):
         Return the intersection of *bbox1* and *bbox2* if they intersect, or
         None if they don't.
         """
-        x0 = np.maximum(bbox1.xmin, bbox2.xmin)
-        x1 = np.minimum(bbox1.xmax, bbox2.xmax)
-        y0 = np.maximum(bbox1.ymin, bbox2.ymin)
-        y1 = np.minimum(bbox1.ymax, bbox2.ymax)
+        x0 = np.maximum(bbox1.x0, bbox2.x0)
+        x1 = np.minimum(bbox1.x1, bbox2.x1)
+        y0 = np.maximum(bbox1.y0, bbox2.y0)
+        y1 = np.minimum(bbox1.y1, bbox2.y1)
         return Bbox([[x0, y0], [x1, y1]]) if x0 <= x1 and y0 <= y1 else None
 
 
