Turn math.isqrt assertion into a comment to clarify its purpose. (GH-14131)

mdickinson · web-flow · commit 2dfeaa9222e2 · 2019-06-16T17:53:21.000+01:00
diff --git a/Modules/mathmodule.c b/Modules/mathmodule.c
@@ -1527,10 +1527,10 @@ Here's Python code equivalent to the C implementation below:
         a = 1
         d = 0
         for s in reversed(range(c.bit_length())):
+            # Loop invariant: (a-1)**2 < (n >> 2*(c - d)) < (a+1)**2
             e = d
             d = c >> s
             a = (a << d - e - 1) + (n >> 2*c - e - d + 1) // a
-            assert (a-1)**2 < n >> 2*(c - d) < (a+1)**2
 
         return a - (a*a > n)
 
