Bug report

from urllib.parse import urlparse
malformed = urlparse("8.8.8.8:1337")._replace(scheme='http').geturl()
print(malformed)

This prints ''http:///8.8.8.8:1337", but should have printed "http://8.8.8.8:1337".
Note the three slashes.
The reason is that the urlunsplit function in Lib/urllib/parse.py checks whether the original url contains a slash, which is not the case, adds a slash and then adds two more slashes.

Your environment

• CPython versions tested on: 3.10.5

Linked PRs

• gh-99901: prepend '/' to url only if netloc is not empty #99910