python
diff --git a/‎library/audioop.po‎
Lines changed: 7 additions & 3 deletions b/‎library/audioop.po‎
Lines changed: 7 additions & 3 deletions
@@ -100,19 +100,19 @@ msgstr "返回片段中所有样本的平均值。"
 msgid ""
 "Return the average peak-peak value over all samples in the fragment. No "
 "filtering is done, so the usefulness of this routine is questionable."
-msgstr ""
+msgstr "返回片段中所有样本的平均峰峰值。由于没有进行过滤，因此该例程的实用性尚存疑。"
 
 #: ../../library/audioop.rst:75
 msgid ""
 "Return a fragment that is the original fragment with a bias added to each "
 "sample.  Samples wrap around in case of overflow."
-msgstr ""
+msgstr "返回一个片段，该片段由原始片段中的每个样本加上偏差组成。在溢出时样本会回卷 (wrap around)。"
 
 #: ../../library/audioop.rst:81
 msgid ""
 "\"Byteswap\" all samples in a fragment and returns the modified fragment. "
 "Converts big-endian samples to little-endian and vice versa."
-msgstr ""
+msgstr "“按字节交换”片段中的所有样本，返回修改后的片段。将大端序样本转换为小端序样本，反之亦然。"
 
 #: ../../library/audioop.rst:89
 msgid ""
@@ -141,6 +141,10 @@ msgid ""
 "(integer) offset into *fragment* where the optimal match started and "
 "*factor* is the (floating-point) factor as per :func:`findfactor`."
 msgstr ""
+"尽可能尝试让 *reference* 匹配 *fragment* 的一部分（*fragment* 应较长）。从概念上讲，完成这些靠从 "
+"*fragment* 中取出切片，使用 :func:`findfactor` 计算最佳匹配，并最小化结果。两个片段都应包含 2 "
+"字节宽的样本。返回一个元组 ``(offset, factor)``，其中 *offset* 是在 *fragment* "
+"中的偏移量（整数），表示从此处开始最佳匹配，而 *factor* 是由 :func:`findfactor` 定义的因数（浮点数）。"
 
 #: ../../library/audioop.rst:115
 msgid ""