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Solutions/1002. Find Common Characters Expand file tree Collapse file tree 2 files changed +52
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lines changed Original file line number Diff line number Diff line change
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+ class Solution {
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+ public List <String > commonChars (String [] words ) {
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+ HashMap <Character , Integer > ansFre = getFre (words [0 ]);
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+ for (int i = 1 ; i < words .length ; i ++){
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+ HashMap <Character , Integer > curFre = getFre (words [i ]);
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+ char c = 'a' ;
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+ for (Map .Entry <Character , Integer > entrySet : ansFre .entrySet ()){
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+ c = entrySet .getKey ();
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+ if (curFre .containsKey (c )){
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+ entrySet .setValue (Math .min (entrySet .getValue (), curFre .get (c )));
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+ }else {
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+ entrySet .setValue (0 );
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+ }
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+ }
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+ }
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+ List <String > ans = new ArrayList <>();
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+ for (Map .Entry <Character , Integer > entrySet : ansFre .entrySet ()){
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+ for (int i = 0 ; i < entrySet .getValue (); i ++){
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+ ans .add (entrySet .getKey ()+"" );
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+ }
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+ }
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+ return ans ;
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+ }
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+ public HashMap <Character , Integer > getFre (String word ){
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+ char [] arr = word .toCharArray ();
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+ HashMap <Character , Integer > hm = new HashMap <>();
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+ for (char c : arr ){
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+ hm .put (c , hm .getOrDefault (c , 0 ) + 1 );
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+ }
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+ return hm ;
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+ }
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+ }
Original file line number Diff line number Diff line change
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+ class Solution :
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+ def commonChars (self , words : List [str ]) -> List [str ]:
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+ def getFre (word ):
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+ hm = {}
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+ for c in word :
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+ hm [c ] = hm .get (c , 0 ) + 1
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+ return hm
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+ ansFre = getFre (words [0 ])
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+ for i in range (1 , len (words )):
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+ curFre = getFre (words [i ])
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+ for key , value in ansFre .items ():
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+ if key in curFre :
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+ ansFre [key ] = min (ansFre [key ], curFre [key ])
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+ else :
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+ ansFre [key ] = 0
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+ ans = []
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+ for key , value in ansFre .items ():
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+ for i in range (value ):
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+ ans .append (key )
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+ return ans
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