You're selecting from callMemberTable and inner joining on it too. You can't do that without giving it an alias.

Ahhh ok that makes sense - I wasn't aware of aliases being a thing! Thanks very much :)

It's common to link to the same table if the data is related. Let's take an HR example as I use that daily.
User id, name, manager id.
1, Fred, 4
2, Alan, 4
3, bob, 4
4, tim, 0

So you can see everyone but Tim has user 4 (Tim) as a manager. In SQL to get Tim's name you have to link into the same table.
However, if I gave you two cups of tea and said 'put sugar in my cup' the first thing you'd ask (hopefully) is 'which cup is yours?'. If they're both blue I can't say 'the blue one'. You need some way to make each one unique.

So in the same way, when you link to the same table, you have to give it a different name .. an alias .. to differentiate it from the other connection to the same table.

For my example, let's call the table people.
Select *
From people
Left join people

This won't work as we have two tables called people.

Select *
From people as p
Left join people as m on m.userId = p.managerId

So now we have two connections .. table p is the main people table and m is another connection to the same table, linked on the manager id to the user id.

We have an issue where manager 0 doesn't exist, but that's ok as Tim is the manager and doesn't have a manager.

Rather than select * we can use select p.* Just to return the main table fields. P.Name regrets to the user name, while m.name would be the managers name.

Hope this makes more sense.
Yell back if it doesn't.

That's really helpful, thank you so much for taking the time!!

@chrisjlocke
I've tried this, and it's now saying that no table with that name exists. I've simplified it to try and figure out what's going wrong. I'm using the following:

SELECT c.callId AS call_id,
kFtsUserTable_content.c0 AS user,
strftime('%d/%m/%Y %H:%M:%S', (c.callTime) / 1000, 'unixepoch') AS call_time
FROM CallMemberTable AS c
LEFT OUTER JOIN c ON kFtsUserTable_content.c1 = c.userId

The error code coming back is "no such table: c"

I'm not sure where I'm going wrong!