File tree Expand file tree Collapse file tree 2 files changed +11
-15
lines changed
Expand file tree Collapse file tree 2 files changed +11
-15
lines changed Original file line number Diff line number Diff line change @@ -179,6 +179,7 @@ \subsubsection{代码}
179179class Solution {
180180public:
181181 bool searchMatrix(const vector<vector<int>>& matrix, int target) {
182+ if (matrix.empty()) return false;
182183 const size_t m = matrix.size();
183184 const size_t n = matrix.front().size();
184185
Original file line number Diff line number Diff line change @@ -104,27 +104,22 @@ \subsubsection{使用栈}
104104\subsubsection {Dynamic Programming, One Pass }
105105\begin {Code }
106106// LeetCode, Longest Valid Parenthese
107- // 时间复杂度O(n),空间复杂度O(1 )
108- // @author 一只杰森(http://weibo.com/2197839961 )
107+ // 时间复杂度O(n),空间复杂度O(n )
108+ // @author 一只杰森(http://weibo.com/wjson )
109109class Solution {
110110public:
111111 int longestValidParentheses(string s) {
112- if (s.empty()) return 0 ;
112+ vector<int> f (s.size(), 0) ;
113113 int ret = 0;
114- int* d = new int[s.size()];
115- d[s.size() - 1] = 0;
116114 for (int i = s.size() - 2; i >= 0; --i) {
117- if (s[i] == ')' ) d[i] = 0;
118- else {
119- int match = i + d[i + 1] + 1; // case: "((...))"
120- if (match < s.size() && s[match] == ')' ) { // found matching ')'
121- d[i] = match - i + 1;
122- if (match + 1 < s.size()) d[i] += d[match + 1]; // more valid sequence after j: "((...))(...)"
123- } else {
124- d[i] = 0; // no matching ')'
125- }
115+ int match = i + f[i + 1] + 1;
116+ // case: "((...))"
117+ if (s[i] == '(' && match < s.size() && s[match] == ')' ) {
118+ f[i] = f[i + 1] + 2;
119+ // if a valid sequence exist afterwards "((...))()"
120+ if (match + 1 < s.size()) f[i] += f[match + 1];
126121 }
127- ret = max(ret, d [i]);
122+ ret = max(ret, f [i]);
128123 }
129124 return ret;
130125 }
You can’t perform that action at this time.
0 commit comments