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Create psf.py
八大排序算法的 Python 实现
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psf.py

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1插入排序
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def insert_sort(lists):
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# 插入排序
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count = len(lists)
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for i in range(1, count):
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key = lists[i]
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j = i - 1
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while j >= 0:
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if lists[j] > key:
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lists[j + 1] = lists[j]
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lists[j] = key
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j -= 1
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return lists
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2希尔排序
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def shell_sort(lists):
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# 希尔排序
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count = len(lists)
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step = 2
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group = count / step
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while group > 0:
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for i in range(0, group):
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j = i + group
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while j < count:
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k = j - group
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key = lists[j]
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while k >= 0:
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if lists[k] > key:
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lists[k + group] = lists[k]
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lists[k] = key
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k -= group
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j += group
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group /= step
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return lists
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3冒泡排序
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def bubble_sort(lists):
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# 冒泡排序
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count = len(lists)
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for i in range(0, count):
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for j in range(i + 1, count):
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if lists[i] > lists[j]:
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lists[i], lists[j] = lists[j], lists[i]
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return lists
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4快速排序
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def quick_sort(lists, left, right):
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# 快速排序
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if left >= right:
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return lists
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key = lists[left]
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low = left
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high = right
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while left < right:
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while left < right and lists[right] >= key:
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right -= 1
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lists[left] = lists[right]
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while left < right and lists[left] <= key:
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left += 1
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lists[right] = lists[left]
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lists[right] = key
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quick_sort(lists, low, left - 1)
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quick_sort(lists, left + 1, high)
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return lists
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5直接选择排序
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def select_sort(lists):
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# 选择排序
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count = len(lists)
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for i in range(0, count):
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min = i
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for j in range(i + 1, count):
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if lists[min] > lists[j]:
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min = j
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lists[min], lists[i] = lists[i], lists[min]
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return lists
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6堆排序
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# 调整堆
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def adjust_heap(lists, i, size):
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lchild = 2 * i + 1
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rchild = 2 * i + 2
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max = i
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if i < size / 2:
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if lchild < size and lists[lchild] > lists[max]:
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max = lchild
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if rchild < size and lists[rchild] > lists[max]:
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max = rchild
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if max != i:
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lists[max], lists[i] = lists[i], lists[max]
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adjust_heap(lists, max, size)
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# 创建堆
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def build_heap(lists, size):
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for i in range(0, (size/2))[::-1]:
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adjust_heap(lists, i, size)
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# 堆排序
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def heap_sort(lists):
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size = len(lists)
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build_heap(lists, size)
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for i in range(0, size)[::-1]:
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lists[0], lists[i] = lists[i], lists[0]
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adjust_heap(lists, 0, i)
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7归并排序
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def merge(left, right):
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i, j = 0, 0
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result = []
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while i < len(left) and j < len(right):
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if left[i] <= right[j]:
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result.append(left[i])
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i += 1
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else:
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result.append(right[j])
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j += 1
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result += left[i:]
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result += right[j:]
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return result
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def merge_sort(lists):
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# 归并排序
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if len(lists) <= 1:
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return lists
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num = len(lists) / 2
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left = merge_sort(lists[:num])
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right = merge_sort(lists[num:])
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return merge(left, right)
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8基数排序
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import math
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def radix_sort(lists, radix=10):
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k = int(math.ceil(math.log(max(lists), radix)))
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bucket = [[] for i in range(radix)]
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for i in range(1, k+1):
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for j in lists:
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bucket[j/(radix**(i-1)) % (radix**i)].append(j)
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del lists[:]
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for z in bucket:
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lists += z
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del z[:]
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return lists

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