Count Trailing Zeroes in Factorial of a Number in Python

In this article, we will learn about the solution to the problem statement given below.

Problem statement − We are given an integer n, we need to count the number of trailing zeros in the factorial.

Now let’s observe the solution in the implementation below −

Example

 Live Demo

# trailing zero
def find(n):
   # Initialize count
   count = 0
   # update Count
   i = 5
   while (n / i>= 1):
      count += int(n / i)
      i *= 5
   return int(count)
# Driver program
n = 79
print("Count of trailing 0s "+"in",n,"! is", find(n))

Output

Count of trailing 0s in 79 ! is 18

Conclusion

In this article, we have learned about how we can make a Python Program to Count trailing zeroes in factorial of a number