Test if Rows Have Similar Frequency in Python

When it is required to check if rows have similar frequency, the ‘all’ operator, the ‘Counter’ method and a simple iteration is used.

Below is a demonstration of the same −

Example

 Live Demo

from collections import Counter

my_list = [[21, 92, 64, 11, 3], [21, 3, 11, 92, 64], [64, 92, 21, 3, 11]]

print("The list is :")
print(my_list)

my_result = all(dict(Counter(row)) == dict(Counter(my_list[0])) for row in my_list )

if(my_result == True):
   print("All rows have similar frequency")
else:
   print("All rows do not have similar frequency")

Output

The list is :
[[21, 92, 64, 11, 3], [21, 3, 11, 92, 64], [64, 92, 21, 3, 11]]
All rows have similar frequency

Explanation

• The required packages are imported into the environment.

• A list of list with integers is defined and is displayed on the console.

• The list in the list of list is converted to a Counter and then to a dictionary.

• It is checked to see if elements in every list occur at the same frequency.

• If yes, a Boolean value is stored in a variable.

• Depending on this Boolean variable, relevant message is displayed on the console.