Neil Robertson vs He Guoqiang [ - ] [ + ]
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| 2018/2019 | |||||||||||
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| World Open Qual (6‑9 Jul 2018) | |||||||||||
| Q Rd 1 | Neil Robertson [8] | 5 | - | 0 | He Guoqiang (a) |
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| 2025/2026 | |||||||||||
| Xi'an Grand Prix (7‑13 Oct 2025) | |||||||||||
| Rd 3 | Neil Robertson [4] | 4 | - | 5 | He Guoqiang [45] |
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