I guess for other types like Array we can convert to/from list and reuse this implementation.

@jdegoes In general for lists.length > 1 there is always a chance the shuffle will yield a list in the same order. Here I test the simplest of scenarios, where the nextInt always returns the same index as the one being swapped with, but obviously there are many ways that can form a "ring" and end up with the same list.

And obviously there are even more combinations which yield a list in diffrent order. Here I chose to only check a "reversed order" scenario.

@ioleo Looks great! Thanks for this contribution, and congratulations on your first ZIO contribution!