String concat code blocks were not equivalent. #260
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If the array is empty, the "bad" code will return `<ul></ul>` and the "good" code will return `<ul><li></li></ul>`.
Although I would prefer this over the for loop:
function inbox(messages) {
items = messages.map(function(message) {
return '<li>' + message.message + '</li>';
});
return '<ul>' + items.join('') + '</ul>';
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👍 for no for-loop. |
Closed
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@hshoff keep it for-loopy or change to a more functional approach? |
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Would love to go functional approach with Thanks for this @joeframbach! 🍻 |
hshoff
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Mar 27, 2015
String concat code blocks were not equivalent.
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If the array is empty, the "bad" code will return
<ul></ul>and the "good" code will return<ul><li></li></ul>.Although I would prefer this over the for loop: