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Week3 homework #14
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Week3 homework #14
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'use strict'; | ||
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{ | ||
const bookTitles = [ | ||
// Replace with your own book titles | ||
'harry_potter_chamber_secrets', | ||
]; | ||
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// Replace with your own code | ||
console.log(bookTitles); | ||
} | ||
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@@ -1 +0,0 @@ | ||
<!-- replace this with your HTML content --> | ||
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@@ -1 +0,0 @@ | ||
/* add your styling here */ | ||
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@@ -20,4 +20,8 @@ f2(y); | |
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console.log(y); | ||
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// Add your explanation as a comment here | ||
/* In the x-code, we are logging the value of x, which has not changed. If we want this code to return 10, | ||
we need to console.log(f1(x)). In the y-code, y is an object. The properties of an object can be altered this way, | ||
so the function changes the value of x to 10. No alteration has been done to the variable reference itself. If f2 | ||
attempted to change the *value* of y (rather than an attribute of its object), it would yield results like the x-code. | ||
For example, if the function is altered, val = { x: 10 }; return val;, it will return { x: 9 } */ | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. I think you get it (?). Another example:
vs objects...
Do you see the difference? There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Yep - I assume it has to do with how JS stores them in memory - when b is set to an object, it's a reference to that object, not a new object with the same details. So whenever a property of 'a' changes, 'b' will 'change' as well (because they're both just pointing to the same object). But when a = 4 and b = a, it's setting b equal to a value of 4 (not pointing to an object). So changing the value of 'a' after that doesn't change the value of 'b'. There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. So in the objects example, both a and b would have a value of { There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 |
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@@ -1,14 +1,17 @@ | ||
'use strict'; | ||
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function createBase(base) { | ||
// Replace this comment and the next line with your code | ||
console.log(base); | ||
return function(number) { | ||
return number + base; | ||
}; | ||
} | ||
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const addSix = createBase(6); | ||
const addSeven = createBase(7); | ||
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console.log(addSix(10)); // returns 16 | ||
console.log(addSix(21)); // returns 27 | ||
console.log(addSeven(21)); // returns 28 | ||
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// Do not change or remove anything below this line | ||
module.exports = createBase; |
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