C++: clearer wording in asExpr doc

jbj · adityasharad · jbj · commit f70a17b858f2 · 2020-08-13T15:27:35.000+02:00
Co-authored-by: Aditya Sharad &lt;6874315+adityasharad@users.noreply.github.com&gt;
diff --git a/cpp/ql/src/semmle/code/cpp/ir/dataflow/internal/DataFlowUtil.qll b/cpp/ql/src/semmle/code/cpp/ir/dataflow/internal/DataFlowUtil.qll
@@ -49,8 +49,7 @@ class Node extends TIRDataFlowNode {
    * of `asExpr`.
    * 
    * If this node strictly (in the sense of `asConvertedExpr`) corresponds to
-   * a `Conversion`, then the result is that `Conversion`'s non-`Conversion`
-   * base expression.
+   * a `Conversion`, then the result is the underlying non-`Conversion` base expression.
    */
   Expr asExpr() { result = this.(ExprNode).getExpr() }
 

Original file line number	Diff line number	Diff line change
`@@ -49,8 +49,7 @@ class Node extends TIRDataFlowNode {`
`49`	`49`	* of `asExpr`.
`50`	`50`	`*`
`51`	`51`	* If this node strictly (in the sense of `asConvertedExpr`) corresponds to
`52`		- * a `Conversion`, then the result is that `Conversion`'s non-`Conversion`
`53`		`- * base expression.`
	`52`	+ * a `Conversion`, then the result is the underlying non-`Conversion` base expression.
`54`	`53`	`*/`
`55`	`54`	`Expr asExpr() { result = this.(ExprNode).getExpr() }`
`56`	`55`