Rust: Implement type inference for ref expression as type equality #19724
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I was debugging an issue where types where not inferred correctly, and realized that for a call like
f(&a)the declared type offs first parameters would not flow toathrough the borrow.This PR fixes that and also removes some logic for ref expressions that doesn't match Rust's type system. Due to implicit dereferencing
&&&&aand&acan seem interchangeable, but the types are distinct. Removing this collapsing doesn't seem to affect the tests.