[MAD PP] Antonio Esteban & Dunnia Alvarez #430
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| @@ -11,13 +18,46 @@ var words = [ | |||
| 'crackpot' | |||
| ]; | |||
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| // Calculating a Sum | |||
| function findLongestWord(){ | |||
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Aqui hay que pasarle un parametro function findLongestWord(array){
| function findLongestWord(){ | ||
| var longitud = 0; | ||
| var mPalabra = ""; | ||
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if(words.length==0){
return(undefined)
}
Esta condición falta in muchas funciones, se utiliza para devolver false si un array esta vacío
| //}, 0); //Pero si no encuentras nada o no hay siguiente, regresa 0 | ||
| //var promedio = sumatoria / array.length; | ||
| var reducer = (accumulator, currentValue)=> accumulator + currentValue; | ||
| console.log(array.reduce(reducer)); |
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Aqui hay que poner return array.reduce(reducer)
| function averageNumbers(array) | ||
| { | ||
| var reducer = (accumulator, currentValue)=> accumulator + currentValue; | ||
| console.log(array.reduce(reducer)/array.length); |
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También aqui poner un return array.reduce(reducer)/array.length
| var reducer = (accumulator, currentValue)=> accumulator + currentValue; | ||
| console.log(array.reduce(reducer)/array.length); | ||
| } | ||
| averageNumbers(numbersAvg) | ||
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Falta la la parte de calcular la media de las palabras, una solución puede ser esta
function averageWordLength(arr){
if(arr.length==0){return undefined}
var suma= 0
for(var k=0; k<words.length; k++){
suma += words[k].length;
}
if(words.length !==0){
return parseInt(suma/words.length);
}
}
| @@ -59,6 +113,15 @@ var wordsFind = [ | |||
| 'truth', | |||
| 'disobedience' | |||
| ]; | |||
| function doesWordExist(array, word) | |||
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os paso la manera mas simple de esta función
function doesWordExist(words, word){
return words.includes(word)
}
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Buen trabajo chicos, miráis las correcciones que ve he mandado para resolver los errores. |
Hasta donde he llegado:Todo menos bonus
Dificultad: media-alta
Comentarios:
Hay cosas que no contemplamos y nos da error
El bonus no nos dio tiempo a mirarlo