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Fix MultipleLocator proposed by @anntzer #7123

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Fix MultipleLocator proposed by @anntzer #7123

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6 changes: 3 additions & 3 deletions lib/matplotlib/ticker.py
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Original file line number Diff line number Diff line change
Expand Up @@ -1614,10 +1614,10 @@ def __call__(self):
def tick_values(self, vmin, vmax):
if vmax < vmin:
vmin, vmax = vmax, vmin
vmin = self._base.ge(vmin)
base = self._base.get_base()
n = (vmax - vmin + 0.001 * base) // base
locs = vmin - base + np.arange(n + 3) * base
nmin = round(self._base.ge(vmin) / base)
nmax = round(self._base.le(vmax) / base)
locs = np.arange(nmin, nmax + 1) * base
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Why can't this code be simplified to: `np.arange(vmin, vmax + base, base)? Floating point errors?

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Sorry… np.arange(self._base.ge(vmin), vmax + base, base) would be the correct solution.

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@anntzer anntzer Sep 19, 2016 •
edited
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Your proposal can include a value that's above vmax (eg. vmin=.5, vmax=2.5, base=1 will return [1, 2, 3]). I guess another solution that's safe against floating point errors is
np.arange(self._base.ge(vmin), self._base.le(vmax) + base / 2, base)
(the + base / 2 should take care of any fpe).

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Yep: I am just concern about the tests that don't make sense to me.

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I had a quick look and am pretty sure that the test values are wrong (i.e. they were picked to match the previous algorithm, which returns out of bounds values; they should be changed to match the new algorithm).

return self.raise_if_exceeds(locs)

def view_limits(self, dmin, dmax):
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