Correct pow() for mpf's to be consistent with mpfr/float's - #690
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Before nan's were handled differently than described in the IEEE 754 standard. Now, as for float's or gmpy2.mpfr's: * pow(1, y) returns 1 for any y, even a nan * pow(x, 0) returns 1 for any x, even a nan Closes mpmath#516 See also: https://en.cppreference.com/w/c/numeric/math/pow https://www.mpfr.org/mpfr-current/mpfr.html#index-mpfr_005fpow https://docs.python.org/3/library/math.html#math.pow
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Before nan's were handled differently than described in the IEEE 754 standard. Now, as for float's or gmpy2.mpfr's:
Closes #516
See also:
https://en.cppreference.com/w/c/numeric/math/pow
https://www.mpfr.org/mpfr-current/mpfr.html#index-mpfr_005fpow
https://docs.python.org/3/library/math.html#math.pow