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DOC: Update documentation of np.linalg.det() #27599

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DOC: Update documentation of np.linalg.det() #27599

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13 changes: 13 additions & 0 deletions numpy/linalg/_linalg.py
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Expand Up @@ -2357,6 +2357,12 @@ def det(a):
The determinant is computed via LU factorization using the LAPACK
routine ``z/dgetrf``.

Due to the limitations of floating-point arithmetic, small numerical
errors may occur when calculating the determinant of a matrix. As a result,
the determinant may return very small non-zero values instead of exactly zero
for singular matrices. To check if a determinant is effectively zero, use
`np.isclose()`.

Examples
--------
The determinant of a 2-D array [[a, b], [c, d]] is ad - bc:
Expand All @@ -2374,6 +2380,13 @@ def det(a):
>>> np.linalg.det(a)
array([-2., -3., -8.])

Checking if the determinant is effectively zero for singular matrices:

>>> a = np.array([[5, 5, 6], [7, 7, 5], [4, 4, 8]])
>>> det = np.linalg.det(a)
>>> np.isclose(det, 0)
True

"""
a = asarray(a)
_assert_stacked_2d(a)
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