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Issue #20750, Enable roundtrip tests for new 5-tuple untokenize. The
constructed examples and all but 7 of the test/test_*.py files (run with -ucpu) pass. Remove those that fail the new test from the selection list. Patch partly based on patches by G. Brandl (#8478) and G. Rees (#12691).
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Lines changed: 38 additions & 14 deletions

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Lib/test/test_tokenize.py

Lines changed: 38 additions & 14 deletions
Original file line numberDiff line numberDiff line change
@@ -578,9 +578,15 @@
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>>> tempdir = os.path.dirname(f) or os.curdir
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>>> testfiles = glob.glob(os.path.join(tempdir, "test*.py"))
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tokenize is broken on test_pep3131.py because regular expressions are broken on
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the obscure unicode identifiers in it. *sigh*
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Tokenize is broken on test_pep3131.py because regular expressions are
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broken on the obscure unicode identifiers in it. *sigh*
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With roundtrip extended to test the 5-tuple mode of untokenize,
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7 more testfiles fail. Remove them also until the failure is diagnosed.
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>>> testfiles.remove(os.path.join(tempdir, "test_pep3131.py"))
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>>> for f in ('buffer', 'builtin', 'fileio', 'inspect', 'os', 'platform', 'sys'):
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... testfiles.remove(os.path.join(tempdir, "test_%s.py") % f)
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...
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>>> if not support.is_resource_enabled("cpu"):
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... testfiles = random.sample(testfiles, 10)
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...
@@ -659,21 +665,39 @@ def dump_tokens(s):
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def roundtrip(f):
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"""
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Test roundtrip for `untokenize`. `f` is an open file or a string.
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The source code in f is tokenized, converted back to source code via
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tokenize.untokenize(), and tokenized again from the latter. The test
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fails if the second tokenization doesn't match the first.
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The source code in f is tokenized to both 5- and 2-tuples.
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Both sequences are converted back to source code via
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tokenize.untokenize(), and the latter tokenized again to 2-tuples.
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The test fails if the 3 pair tokenizations do not match.
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When untokenize bugs are fixed, untokenize with 5-tuples should
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reproduce code that does not contain a backslash continuation
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following spaces. A proper test should test this.
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This function would be more useful for correcting bugs if it reported
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the first point of failure, like assertEqual, rather than just
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returning False -- or if it were only used in unittests and not
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doctest and actually used assertEqual.
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"""
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# Get source code and original tokenizations
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if isinstance(f, str):
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f = BytesIO(f.encode('utf-8'))
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try:
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token_list = list(tokenize(f.readline))
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finally:
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code = f.encode('utf-8')
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else:
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code = f.read()
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f.close()
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tokens1 = [tok[:2] for tok in token_list]
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new_bytes = untokenize(tokens1)
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readline = (line for line in new_bytes.splitlines(keepends=True)).__next__
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tokens2 = [tok[:2] for tok in tokenize(readline)]
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return tokens1 == tokens2
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readline = iter(code.splitlines(keepends=True)).__next__
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tokens5 = list(tokenize(readline))
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tokens2 = [tok[:2] for tok in tokens5]
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# Reproduce tokens2 from pairs
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bytes_from2 = untokenize(tokens2)
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readline2 = iter(bytes_from2.splitlines(keepends=True)).__next__
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tokens2_from2 = [tok[:2] for tok in tokenize(readline2)]
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# Reproduce tokens2 from 5-tuples
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bytes_from5 = untokenize(tokens5)
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readline5 = iter(bytes_from5.splitlines(keepends=True)).__next__
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tokens2_from5 = [tok[:2] for tok in tokenize(readline5)]
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# Compare 3 versions
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return tokens2 == tokens2_from2 == tokens2_from5
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# This is an example from the docs, set up as a doctest.
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def decistmt(s):

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