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Fix an issubclass failure for protocols with overloaded methods #9904

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Feb 20, 2022
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2 changes: 1 addition & 1 deletion mypy/subtypes.py
Original file line number Diff line number Diff line change
Expand Up @@ -735,7 +735,7 @@ def non_method_protocol_members(tp: TypeInfo) -> List[str]:

for member in tp.protocol_members:
typ = get_proper_type(find_member(member, instance, instance))
if not isinstance(typ, CallableType):
if not isinstance(typ, (Overloaded, CallableType)):
result.append(member)
return result

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13 changes: 12 additions & 1 deletion test-data/unit/check-protocols.test
Original file line number Diff line number Diff line change
Expand Up @@ -2270,7 +2270,7 @@ y: PBad = None # E: Incompatible types in assignment (expression has type "None
[out]

[case testOnlyMethodProtocolUsableWithIsSubclass]
from typing import Protocol, runtime_checkable, Union, Type
from typing import Protocol, runtime_checkable, Union, Type, Sequence, overload
@runtime_checkable
class P(Protocol):
def meth(self) -> int:
Expand All @@ -2292,6 +2292,17 @@ if issubclass(cls, P):
reveal_type(cls) # N: Revealed type is "Type[__main__.C]"
else:
reveal_type(cls) # N: Revealed type is "Type[__main__.E]"

@runtime_checkable
class POverload(Protocol):
@overload
def meth(self, a: int) -> float: ...
@overload
def meth(self, a: str) -> Sequence[float]: ...
def meth(self, a):
pass

reveal_type(issubclass(int, POverload)) # N: Revealed type is "builtins.bool"
[builtins fixtures/isinstance.pyi]
[typing fixtures/typing-full.pyi]
[out]
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