[po] auto sync bot

zhsj · zhsj · commit fe509f582afe · 2019-05-25T16:40:53.000+08:00
diff --git a/faq/programming.po b/faq/programming.po
@@ -1597,11 +1597,11 @@ msgstr "如何按其他列表中的值对一个列表进行排序？"
 msgid ""
 "Merge them into an iterator of tuples, sort the resulting list, and then "
 "pick out the element you want. ::"
-msgstr ""
+msgstr "将它们合并到元组的迭代器中，对结果列表进行排序，然后选择所需的元素。"
 
 #: ../../faq/programming.rst:1386
 msgid "An alternative for the last step is::"
-msgstr ""
+msgstr "最后一步的替代方案是::"
 
 #: ../../faq/programming.rst:1391
 msgid ""
@@ -1629,6 +1629,7 @@ msgid ""
 "which embody both the data (attributes) and code (methods) specific to a "
 "datatype."
 msgstr ""
+"``类`` 是通过执行类语句创建的特定对象类型。``类对象`` 被当作模板来创建实例对象，实例对象包含了特定于数据类型的数据（属性）和代码（方法）。"
 
 #: ../../faq/programming.rst:1410
 msgid ""
@@ -1639,17 +1640,20 @@ msgid ""
 "for a mailbox, and subclasses such as ``MboxMailbox``, ``MaildirMailbox``, "
 "``OutlookMailbox`` that handle various specific mailbox formats."
 msgstr ""
+"类可以基于一个或多个的其他类，称之为基类（ES），它继承基类的属性和方法，这样就可以通过继承来连续地细化对象模型。例如：您可能有一个 "
+"``Mailbox`` 类提供邮箱的基本访问方法.，它的子类 ``MboxMailbox``, ``MaildirMailbox``, "
+"``OutlookMailbox`` 用于处理各种特定邮箱格式。"
 
 #: ../../faq/programming.rst:1419
 msgid "What is a method?"
-msgstr ""
+msgstr "什么是方法？"
 
 #: ../../faq/programming.rst:1421
 msgid ""
 "A method is a function on some object ``x`` that you normally call as "
 "``x.name(arguments...)``.  Methods are defined as functions inside the class"
 " definition::"
-msgstr ""
+msgstr "``方法`` 实际上就是类定义中的函数。对于某个对象 ``x`` 上的方法，通常称为 ``x.name(arguments...)`` 。"
 
 #: ../../faq/programming.rst:1431
 msgid "What is self?"
@@ -1662,6 +1666,8 @@ msgid ""
 " c)`` for some instance ``x`` of the class in which the definition occurs; "
 "the called method will think it is called as ``meth(x, a, b, c)``."
 msgstr ""
+"Self 只是 ``方法`` 的第一个参数的常规名称。例如：对于某个类的某个实例 ``x`` ，其方法 ``meth(self, a, b, c)`` "
+"实际上应该被称为 ``x.meth(a, b, c)`` ；对于被调用的方法会被称为 ``meth(x, a, b, c)`` 。"
 
 #: ../../faq/programming.rst:1438
 msgid "See also :ref:`why-self`."
@@ -2180,7 +2186,7 @@ msgstr ""
 msgid ""
 "When I edit an imported module and reimport it, the changes don't show up.  "
 "Why does this happen?"
-msgstr "当我编辑导入的模块并重新导入它时，更改不会显示。为什么会这样？"
+msgstr "当我编辑了导入过的模块并重新导入它时，这些变化没有显示出来。为什么会这样？"
 
 #: ../../faq/programming.rst:1869
 msgid ""
diff --git a/library/importlib.po b/library/importlib.po
@@ -11,6 +11,7 @@
 # leollon <mssm.good@outlook.com>, 2019
 # Freesand Leo <yuqinju@163.com>, 2019
 # Shengjing Zhu <zsj950618@gmail.com>, 2019
+# Yixin Qian <qianyixin1992@gmail.com>, 2019
 # 
 #, fuzzy
 msgid ""
@@ -19,7 +20,7 @@ msgstr ""
 "Report-Msgid-Bugs-To: \n"
 "POT-Creation-Date: 2019-01-01 10:14+0900\n"
 "PO-Revision-Date: 2017-02-16 23:15+0000\n"
-"Last-Translator: Shengjing Zhu <zsj950618@gmail.com>, 2019\n"
+"Last-Translator: Yixin Qian <qianyixin1992@gmail.com>, 2019\n"
 "Language-Team: Chinese (China) (https://www.transifex.com/python-doc/teams/5390/zh_CN/)\n"
 "MIME-Version: 1.0\n"
 "Content-Type: text/plain; charset=UTF-8\n"
@@ -763,6 +764,9 @@ msgid ""
 "does not matter if the package and its data file(s) are stored in a e.g. zip"
 " file versus on the file system."
 msgstr ""
+"从这个抽象基类的视角出发，*resource* 指一个包附带的二进制文件。常见的如在包的  ``__init__.py`` "
+"文件旁的数据文件。这个类存在的目的是为了将对数据文件的访问进行抽象，这样包就和其数据文件的存储方式无关了。不论这些文件是存放在一个 zip "
+"文件里还是直接在文件系统内。"
 
 #: ../../library/importlib.rst:491
 msgid ""
@@ -775,6 +779,9 @@ msgid ""
 " class are expected to directly correlate to a specific package (instead of "
 "potentially representing multiple packages or a module)."
 msgstr ""
+"对于该类中的任一方法，*resource* 参数的值都需要是一个表示文件名称的 :term:`路径类对象`。这意味着任何子文件夹的路径都不该出现在 "
+"*resouce* "
+"参数值内。因为对于阅读器而言，包的位置就代表着「文件夹」路径。与inwei，文件夹和文件名就分别代表包和资源，这也是该类的实例都需要和一个包直接关联（而不是潜在指代很多包或者一整个模块）的原因。"
 
 #: ../../library/importlib.rst:502
 msgid ""
@@ -785,6 +792,9 @@ msgid ""
 " with this ABC should only be returned when the specified module is a "
 "package."
 msgstr ""
+"加载 resource 的各类加载器需要提供一个名为 ``get_resource_loader(fullname)`` "
+"的方法以返回一个视线了改抽象基类接口的对象。如果 fullname 参数指定的模块不是一个包，该方法应返回 "
+":const:`None`。只有在指定模块是一个包的情况下，该方法才应当返回一个和该抽象基类兼容的对象。"
 
 #: ../../library/importlib.rst:513
 msgid ""
