(?<!\d)\d+\.\d+ should match the numbers at the end of the lines and yet it won’t. What am I doing wrong?
To put this into easier form:
(nota digit) (1ormore digit) (literal dot) (1ormore digit)
As far as I can see in that text, none of them end with "5.4” or "3.6” or "0.0”, so no your regex wont work
Maybe change the middle " \d+" into “\d*” , or surround the “\d+\.” with a question mark group?
surround the “\d+.” with a question mark group?
If you’re expecting decimals, that’s the preferred solution:
(?<!\d)(\d+\.)?\d+(?=\s*$)Otherwise you could do simply
(?<!\d)\d+(?=\s*$)I added the lookahead
(?=\s*$)to match digits at the end of the line only with possible trailing spaces.Whaaaaaaa, thank you!
Thank you. Every time someone shows me something regarding regex, I feel like I’m getting lessons from a deity.
You actually helped me out lots. I switched it to
(?<!\d)\.*\d{1}+thanks to your comment and it kinda did the job, so thank you.oh nice solution, quite elegant
It’s a terrible solution, but it works somewhat. Thanks for being nice.
What am I doing wrong?
Not specifying the regex engine you use, first of all. Second, also describe what you mean by numbers that you want to match.
Not specifying the regex engine you use
Sorry, I have no clue.
Second, also describe what you mean by numbers that you want to match.
So you see in the screenshot, there’s a random number at the end of some of the lines, I’m trying to match that.
Sorry, I have no clue.
What do you use to apply your regex? Programming language, library, command line tool etc.
there’s a random number at the end of some of the lines, I’m trying to match that.
Is it decimal? One digit or multiple digits? Natural, rational?
Sorry it took so long to get back to you, I was trying to find a type of some sort.
The app offers this https://github.com/gedoor/legado/blob/master/app/src/main/assets/web/help/md/regexHelp.md Which I hope you find fruitful as an indication.
What do you use to apply your regex?
An ePub Reader called Legado
Is it decimal? One digit or multiple digits? Natural, rational?
In the screenshot above, you can see it differs. I feel like I’m not doing your kindness justice with my sparse information, sorry! 🥺
BTW if you don’t need to capture the number,
\d$should match what you need. If regex syntax supports\d, of course.The number is the bit I want to capture.
(?<!\d)-> Not sure why you’re doing this.\d+\.-> Look for at one or more digits followed by a period. None of the sentences have numbers before the period, and if the previous section didn’t exclude them, this would.\.\d+-> look for a period followed immediately by one or more numbers. This should get most of the trailing 0’s, but you’ll miss the ones on their own newline and following a quotations mark.\.0\-> If you only have a single character you’d like to remove, there’s no harm in enumerating it.
