- Aptitude - Home
- Aptitude - Overview
- Quantitative Aptitude
Aptitude - Pipes & Cisterns Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Pipes & Cisterns. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - A tap can fill storage in 8 hours and another tap can discharge it in 16 hours. In the event that both the taps are open, the time taken to fill the tank will be:
Answer : C
Explanation
Net part filled in 1 hr = (1/8 ? 1/16)= 1/16 Total time taken to fill the tank = 16 hrs.
Q 2 - A channels can fill a tank in x hours and another funnel can exhaust it in y (y>x) hours. In the event that both the funnels are open, in how long will the tank be filled?
Answer : D
Explanation
Work done by filling pipe in 1 hr = 1/x Work done by emptying pipe in 1 hr = 1/y Net filling work done by both in 1 hr = (1/x- 1/y) = (y-x)/xy ∴The tank will be filled in xy/(y-x) hrs.
Q 3 - A storage has two funnels. One can fill it with water in 8hours and the other can exhaust it in 5 hours. In how long will the reservoir be purged if both the channels are opened together when 3/4 of the storage is now loaded with water?
Answer : C
Explanation
Net part emptied by both in 1 hr = (1/5-1/8)= 3/40 3/40 part is emptied in 1 hr. 3/4 part will be emptied in (40/3*3/4) hrs = 10 hrs.
Q 4 - Two pipes A and B can fill a tank in 15 minutes and 20 minutes separately. Both the channels are opened together. Be that as it may, following 4 minutes, pipe is turned off. What is the aggregate time required to fill the tank?
Answer : D
Explanation
Part filled by both in 4 min. = 4*(1/15+1/20)= (4*7/60)= 7/15 Part unfilled = (1-7/15) = 8/15 1/20 part is filled by B in 1 min. 8/15 part is filled by B in (20*8/15) min. = 32/3 min = 10 min 40 sec. Total time taken = (4 min+10 min 40 sec.) = 14 min 40 sec.
Q 5 - A tank is fitted with two taps A and B. A can fill the tank totally in 45 minutes and B can purge the full tank in 60 minutes. On the off chance that both the taps are opened on the other hand for 1 minute, then in what amount of time the unfilled tank will be filled totally?
Answer : D
Explanation
Work done by A in 1st minutes and B 2nd minute= (1/45- 1/60)= 1/180 Part filled in 2 min = 1/180 Part filled in 358 min = (1/360*358) = 358/360 = 179/180 Remaining part = (1-179/180) = 1/180 1/45 part is filled by A in (45*1/180) min= 1/4 min. Total time taken to fill it = 358 1/4 min = 5 hrs.58 min 15 sec.
Q 6 - Three funnels A, B; C can fill a tank in 6 hours. In the wake of working at it together for 2 hours, C is shut and A and B can fill the remaining part in 7 hours. The quantity of hours taken by C alone to fill the tank is:
Answer : C
Explanation
Part filled by (A+B+c) in 2 hours= (1/6*2)=1/3 2/3 part is filled by (A+B) in 7 hours. Whole is filled by (A+B) in (7*3/2) hr=21/2hrs. Part filled by C in 1 hour = (1/6-2/21) = 3/42 = 1/14 ∴C alone can fill it in 14 hours.
Q 7 - A break in the base of a tank can purge the full tank in 6 hours. A channel funnel fills water at the rate of 4 liters for each moment. At the point when the tank is full, the channel is opened and because of the break, the tank is void in 8 hours. The limit of the tank is
Answer : B
Explanation
Part filled in 1 hour = (1/6-1/8)= 1/24 So, the inlet can fill the tank in 24 hours. Capacity of the tank= volume of water that flows in 24 hrs = (4*60*24) ltr. = 5760 liters.
Q 8 - A channel can fill a reservoir in 12 minutes and another funnel can fill it in 15 minutes, however a third pipe can discharge it in 6 minutes. The initial two funnels are kept open for 5 minute to start with and after that the third pipe is additionally opened. In what time is the storage exhausted?
Answer : D
Explanation
Part filled in 5 min= 5*(1/12+1/15)= (5*9/60)= 3/4 Part emptied in 1 min. when all the pipes are opened= 1/6 ? (1/12+1/15) = (1/6- 3/20) = 1/60 1/60 part is emptied in 1 min. 3/4 part will be emptied in (60*3/4) min = 45 min.
Q 9 - A pump can fill a tank with water in 2 hours. Because of a leak in the tank, it takes 7/3 hours to fill the tank. The leak can empty the filled tank in?
Answer : D
Explanation
Part of the tank filled by the pump in 1 hour = 1/2 Part of the tank filled by the pump in 1 hour because of the leak = 3/7 ∴ Part of the tank emptied by the leak in 1 hour = 1/2 - 3/7 = 1/14 ∴ Leak will empty the tank in 14 hours.
Q 10 - A cistern can be filled by two pipes in 20 and 30 min respectively. Both pipes being open, when must the first pipe be turned off so that so that the cistern may be filled in 10 min more?
Answer : D
Explanation
In 1 min both pipes can fill = 1/20 + 1/30 = 1/12 In 10 min second pipe can fill = (1/30)*10 = 1/3 part Part of cistern filled by both the pipes = 1 - 1/3 = 2/3 1/12 part is filled in 1 min ∴ 2/3 part will be filled in 12*2/3 = 8 min Hence, first first pipe should be turned off after 8 min.