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Speed & Distance - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Speed & Distance. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - In what time can Somali spread a separation of 400m, in the event that she keeps running at a rate of 20 km/hr?
Answer : A
Explanation
20 km/hr = (20*5/18) m/sec =50/9m/sec. Time taken to cover 400 m = (400*9/50) sec= 72 sec. = 6/5 min.
Q 2 - The proportion between the paces of two trains is 7:8. On the off chance that the second prepare keeps running in 5 hours 400 km, the pace of the first prepare is :
Answer : A
Explanation
Let the speed of first train be 7x km/hr. Then the speed of the second train is 8x km/hr. But speed of the second train=400/5km/hr=80 km/hr ∴8x=80⇒x=10. Hence the speed of first train is (7*10) km/hr=70 km/hr.
Q 3 - By strolling at 3/4 of his standard speed, a man achieves his office 20 min. later than Normal. His standard time is:
Answer : B
Explanation
At a speed of 3/4 of the usual speed , time taken = 4/3 of usual time ∴ (4/3 of usual time) - (usual time) = 20 min. Let the usual time be x min. then, (4x/3 - x) = 20 ⇒x = 60 min. ∴usual time is 60 min.
Q 4 - A certain separation is secured at a sure speed. On the off chance that half of this separation is secured in twofold the time, the proportion of the two paces is:
Answer : A
Explanation
Let x kms be covered in y hrs. then, first speed = x/y km/hr Again, x/2 km is covered in 2y hrs. ∴new speed = (x/2 * 1/2y) km/hr = (x/4y)km/hr Ratio of speeds = x/y : x/4y = 1:1/4 = 4:1
Q 5 - The velocities of three autos in the proportion 2:3:4. The proportion of the times taken by these autos to venture to every part of the same separation is:
Answer : D
Explanation
Ratio of time taken = 1/2: 1/3: 1/4 = 6:4:3
Q 6 - A constable is 114 m behind a thief. The constable runs 21 m and the thief15 m in a moment. In what the reality of the situation will become obvious eventually constable catch the criminal?
Answer : D
Explanation
(21-15) m i.e.6m is covered in 1 min. 114m will be covered in (1/6*114) min=19 min.
Q 7 - The separation between two stations A and B is 220 km. A train leaves a towards B at 80 km/hr. After thirty minutes, another train leaves B towards An at 100 km/hr. The separation of the point where the two trains meet, from A is:
Answer : A
Explanation
Let the required distance be x km. then, x/80 - (220-x)/100 = 1/2 ⇒ 5x-4 (220-x) = 200 ⇒9x = 1800 ⇒x = 120 Hence the required distance is 120 km.
Q 8 - Laxman needs to cover 6 km in 45 minutes. On the off chance that he covers one portion of the separation in 2/3 rd time, what ought to be his rate to cover the remaining separation in the remaining time?
Answer : A
Explanation
Time left = (1/3*45/60)hr = 1/4 hr, distance left = 3 km Speed required = 3/ (1/4) km/hr = 12 km/hr
Q 9 - A train covers a separation in 50 minutes, in the event that it keeps running at a velocity of 48 km/hr on a normal. The velocity at which the train must rushed to diminish the season of voyage to 40 minutes, will be:
Answer : C
Explanation
Distance = (speed * time) = (48*50/60) km = 40 km New time taken = 40/60 hr = 2/3 hr New speed = (40*3/2) km/hr = 60 km/hr
Q 10 - A train voyaged separations of 10 km, 20 km and 30 km at rates of 50 km/hr, 60 km/hr and 90 km/hr separately. The normal rate of the train was
Answer : C
Explanation
Total distance covered = (10+20+30) km = 60 km Total time taken = (10/50 + 20/60+ 30/90) hr = (1/5+1/3+1/3) hr = 13/15 hr. Average speed = (60* 15/13) km/hr = (900/13) km/hr = 69.23 km/hr